if p(x) = x^3-3x^2 +2x-3 evalute p(1)+p(-1)
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Answered by
1
p(1)=1-3+2-3=-3
p(-1)=-1-3-2-3=-9
p(1)+p(-1)=-12
p(-1)=-1-3-2-3=-9
p(1)+p(-1)=-12
mehtamanav19p9jg8y:
It is wrong p(-1) is worng check your signs
my answer is correct, dude
my answer is correct, dude.
akshat mark me as brailest , because my answer only correct, his answer is wrong
Answered by
1
p(1) = 1^3 - 3(1)^2 +2(1) -3
= 1-3+2-3
= -2-1 = -3
p(-1)= -1^3 -3(-1)^2+2(-1)-3
= -1+3-2-3
= 2-5= -3
p(1) + p(-1)
= -3 + -3
= -3-3 = -6
= 1-3+2-3
= -2-1 = -3
p(-1)= -1^3 -3(-1)^2+2(-1)-3
= -1+3-2-3
= 2-5= -3
p(1) + p(-1)
= -3 + -3
= -3-3 = -6
ok
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Mere answer ke upar mark as brainliest ka option hai click krdo
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Thanks
kerdiya
thanks
Thanks
-3*(-1)^2= 3 , you marked as -3
because-1^2=1
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