if p(x)=x^3-3x^2+2x-3 find the value of p(1)+p(-1)
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komalprajapat:
thanks it helps me
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Answer:
p(x)=x^3-3x^2+2x-3
p(1)=1(1)^3-3(1)^2+2(1)-3
=1-3+2-3
=1-1-3
=-3 - 1
p(-1)= -1^3-3(-1)^2+2(-1)-3
= -1-3-2-3
= -4-5
= -9 - 11
1+11
(-3)+(-9)
-12
i hope this is helpful to you........................
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