Math, asked by pokemonisbae4289, 1 year ago

If p(x)= x^3+ 3x^2- 2x+4, then find the value of p(2)+ p(-2)- p(0)

Answers

Answered by mehersangram100
1

p(2)+p(-2)-p(0)=20+12-4=28


Answered by BrainlyKingdom
2

Answer

p(2) + p(-2) - p(0) = 28

Step By Step Explanation

p(2) + p(-2) - p(0)

= [2³ + 3(2)² - 2(2) + 4] + [(-2)³ + 3(-2)² - 2(-2) + 4] - [0³ + 3(0)² - 2(0) + 4]

= [8 + 3(4) - 4 + 4] + [-8 + 3(4) - (-4) + 4] - [0 + 3(0) - 0 + 4]

= [8 + 12 - 4 + 4] + [-8 + 12 + 4 + 4] - [0 + 0 - 0 + 4]

= [8 + 12] + [-8 + 12 + 8] - [4]

= 20 + 12 - 4

= 32 - 4

= 28

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