Question

if p(x)=x^3-3x^2+2x find p(-2)​

Answer 1

Step-by-step explanation:

p(-2) = -2³-3×(-2)²+2×(-2)

= -8-(3×4)-4

=-8-12-4=-24

p(-2)=-24

Answer 2

Answer:

p(-2) = 0

p = 2

Now,

$p(x) = {x}^{3} - 3{x}^{2} + 2x \\ p(2) = {2}^{3} - 3 ({2})^{2} + 2(2) \\ p(2) = 8 - 12 + 4 \\ p(2) = - 4 + 4 \\ p(2) = 0$