Question

if p(x)= x^3-3x^2+2x,then find the value of p(1)

Answer 1

$\huge{\mathcal{Hi\: there!}}$

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P ( x ) = x³ - 3x² + 2x

P ( 1 ) = 1³ - 3 ( 1 )² + 2 × 1

P ( 1 ) = 1 - 3 + 2

P ( 1 ) = 3 - 3

P ( 1 ) = 0

Hence, the value of p (1) is 0.

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Answer 2

Answer:

p(1) = 0

Step-by-step explanation:

Given,

p(x)= x³ -3x²+2x

To find,

The value of p(1)

Solution:

p(x) = x³ -3x²+2x

The value of p(1) is obtained by substituting the value of the variable as '1'

p(1) = 1³ -3x1²+2x1

= 1 - 3 +2

= 0

∴p(1) = 0

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