Question

if p(x)=x^3-3x^2a+2a^2x+b is divisible by (x-a) then find value of b​

Answer 1

Answer:

If x - a is a factor of x^3 - 3x^2a + 2a^2x + b , then the value of b

Let P(x) = x^3 - 3x^2a + 2a^2x + b Given, (x - a) is a factor of P(x) P(a) = 0 (a)^3 - 3(a)^2a + 2a^2(a) + b = 0 a^3 - 3a^3 + 2a^3 + b = 0 3a^3 - 3a^3 + ...

Answer 2

Step-by-step explanation:

Given, (x-a) is a factor then

P(a)=0

P(a) = a³-3a².a+2a².a+b=0

= a³-3a³+2a³+b=0

= 3a³-3a³+b=0

= b=0

Hence the Value of b=0