Question

if p(x) = x^3-4x^2+x+6,then find the value of p(3)

Answer 1

ans: 0

Step-by-step explanation:

given,p(x)=x^3-4x^2+x+6

therefore,p(3)=3^3-4×3^2+3+6

=27-36+9

=36-36=0