Question

if p(x)=x^3-4x+3, evaluatep(2)-p(-1)+p(1/2) ​

Answer 1

Answer:

p(x)=x^3-4x+3

p(2)=(2)^3-4*2+3=8-8+3=3

p(-1)=(-1)^3-4(-1)+3= -1+4+3=6

p(1/2)=(1/2)^3-4(1/2)+3=(1/8)-2+3=[(1-16)/8]+3

p(1/2)=(-15/8)+3=(-15+24)/8=9/8

p(2)-p(-1)+p(1/2)= 3-6+(9/8)= -3+(9/8)=(-24+9)/8

p(2)-p(-1)+p(1/2)= -15/8