Question

if p(x)=x^3+5x^2+4 then find the vallue of allfa bita gamma ​

Answer 1

$\green{x {}^{3} + 4x {}^{2} - 5x - 2}$

The expression is in the form :-

$\red{\bf \: ax {}^{3} + bx {}^{2} + cx + d}$

Then :-

$\pink\leadsto(a =1) (b =4 ) \\ ( 6 = 5)(d = - 2)$

$\blue{\alpha + \beta + \gamma = \frac{ - b}{a} = \frac{ - 4}{1} = \bf - 4}$

$\boxed{ = \alpha \beta + \beta \gamma + \gamma \alpha }$

$= \frac{c}{a} = \frac{ - 5}{1} = \tt - 5$

At last :-

$\orange{\bigstar\alpha \beta \gamma = \frac{ - d}{a} = \frac{( -2) }{1} = \bf = 2}$