Question

if p(x) = x^3 - 6x^2 + 11x - 6, then the value of p(1) is
0
3
9
-4

give ans only

Answer 1

QUESTION:

if p(x) = x^3 - 6x^2 + 11x - 6, then the value of p(1).

ANSWER :

We have to find p(1)

then we put one in polynomial at the place of x.

$p(x) = {x}^{3} - 6 {x}^{2} + 11x - 6$

$p(1) = {1}^{3} - 6( {1})^{2} + 11 \times 1 - 6 \\ p(1) = 1 - 6 + 11 - 6 \\ p(1) = 1 + 11 - 6 - 6 \\ p(1) = 12 - 12 \\ p(1) = 0$

FINAL ANSWER :

$p(1) = 0$

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