Question

If p (x)= x^3-ax^+bx+3 leaves a remainder -19 when divided by x+2 and a remainder 17 divided by x-2. Prove that a+b=6

Answer 1

P(x) =x³-ax²+bx+3
P(-2) =-19
P(2) =17
a=1
b=5
a+b=5+1=6