Question

if p(x)=x^3,then the value of p(1)+p(-1) is equal to

Answer 1

Answer:

$p(x) = {x}^{3 } \\ p(1) = {1}^{3} \\ = 1 \\ p( - 1) = { - 1}^{3} \\ = - 1 \\ p(1) + p( - 1) = 1 + ( - 1) \\ = 0 \\ \\ hope \: that \: it \: will \: help \: u$

Answer 2

Answer:

p(1) =(1) ³=1

p(-1) =(–1) ³=–1

p(1) +p(–1) =1+(–1) =1–1=0