Question

If p(x) = x^3+ x^2- 2x + 4 , then find the value of p(2) + p(-2)- p(0)​

Answer 1

Answer:

12 is the answer

Step-by-step explanation :-

p(x)=x^3+x^2-2x+4

p(2)=(2×2×2)+(2×2)-(2×2)+4

p(2)=8+4-4+4

p(2)=12

p(-2)=(-2×-2×-2)+(-2×-2)-(2×-2)+4

p(-2)= -8+4+4+4

p(-2)= 4

p(0)=(0×0×0)+(0×0)-(2×0)+4

p(0)=0+0-0+4

p(0)=4

p(2)+p(-2)-p(0)

= 12 + 4 - 4

= 12 Answer

I hope my answer is correct