Question

if p(x) = x^3 +x^2-9x-9, then find p(0and p(-3)​

Answer 1

Answer:

p(0) =

$= {0}^{3} + {0}^{2} - (9 \times 0) - 9$

= 0 + 0- 0- 9

= -9

p(-3) =

$= {( - 3)}^{3} + {( - 3)}^{2} - 9 \times ( - 3) - 9$

= -27 + 9 + 27 - 9

= 0

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