Question

if p(x)= x^3+x^2+ root 3x + root 3 find the value of p(-root 3) is​

Answer 1

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Answer 2

Step-by-step explanation:

P(x) = x^3 + x^2 + root 3x + root 3

Substituting -root 3 in the place of x

p(-root 3) = (-root 3)^3 + (-root 3)^2 + root 3 (-root 3) + root 3

p(-root 3) = -3root 3 + 3 - 3 + root 3

p(-root 3) = -3 root 3 + root 3 + 3 - 3

p(-root 3) = -2 root 3

Therefore p(-root 3) is -2 root 3

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