Question

if p(x)=x^3+x^2+x+1,then p(-1)​

Answer 1

p(x)=x^3+x^2+x+1

or, p(-1) = (-1)^3 + (-1)^2 +(-1) +1

= -1+1-1+1

= 0

Thus, p(-1) =0

Answer 2

Step-by-step explanation:

= -1 + 1 -1 + 1 = 0

p(-1) = 0

Hope this helps