if p(x)=x^4-2x^3+3x^2-ax+b is a polynomial such that when it is divided by x-1 and x+1 the remainders are respectively 5 and 19 .determine the remainder when p(x) is divided by(x-2).find 'a' and 'b'
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0
remainder = 10
a = 5
b = 8
a = 5
b = 8
tssuyambulingam:
where is the explanation............ and the steps.................
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P(x) = x⁴ - 2 x³ + 3 x² - a x + b
reminder of the polynomial when divided by (x - k) is P(k). substitute k in place of x.
P(1) = 5 => 1 -2 +3 - a + b = 5
b - a = 3
P(-1) = 19 => 1 +2 + 3 + a + b = 19
a + b = 13
adding the two equations we get: 2 b = 16 => b = 8
a = 5
reminder when P(x) is divided by (x-2) :
= P(2)
= 2^4 - 2 2^3 + 3 2^2 - 5 * 2 + 8
= 10
reminder of the polynomial when divided by (x - k) is P(k). substitute k in place of x.
P(1) = 5 => 1 -2 +3 - a + b = 5
b - a = 3
P(-1) = 19 => 1 +2 + 3 + a + b = 19
a + b = 13
adding the two equations we get: 2 b = 16 => b = 8
a = 5
reminder when P(x) is divided by (x-2) :
= P(2)
= 2^4 - 2 2^3 + 3 2^2 - 5 * 2 + 8
= 10
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