Question

If p(x)=x^4-x^2+20 find the value of p(-2)+p(-3)​

Answer 1

The polynomial given : p(x) = x⁴ – x² + 20

Finding p(–2) for p(x) = x⁴ – x² + 20 :

⟹ x⁴ – x² + 20

⟹ (–2)⁴ – (–2)² + 20

⟹ 16 – 4 + 20

⟹ 12 + 20

⟹ 32

Finding p(–3) for p(x) = x⁴ – x² + 20 :

⟹ x⁴ – x² + 20

⟹ (–3)⁴ – (–3)² + 20

⟹ 81 – 9 + 20

⟹ 72 + 20

⟹ 92

Finding the value of p(–2) + p(–3) :

⟹ 32 + 92

⟹ 124

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⟹ Therefore, the value of p(–2) + p(–3) is 124 when p(x) = x⁴ – x² + 20.