If p(x) = x + 7x + 3 and q(x) = 2x - 3, then find the value of p(x) q(x)
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Answer:
p(x+7x+3p) q(2x-3)
= (px+7px+3p)(2qx-3q)
=2pqx^2+14pqx^2+6pqx-3pqx-21pqx-9pq
= 16pqx^2-18pqx-9pq
Step-by-step explanation:
First we will put the value of x in the bracket of p then we will do the same with q will put the value of x in the bracket of q.
then we will first multiply p from all its term of the bracket then will repeat the same proses with q.
after getting two bracket and their terms we will again multiple each term of the 1st bracket with the term of second bracket.
then we will get a linear equation and according to that we will perform the operation of the like terms (as per the operation given in the question.)
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