If P = {x : x is a multiple of 3, 1 < x < 20} and Q = {x : x is an even natural number < 15} then find P ∩ Q
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P = {x : x is a multiple of 3, 1 < x < 20}
P = { 3, 6, 9, 12, 15, 18 }
Q = {x : x is an even natural number < 15}
Q = { 2, 4, 6, 8, 10, 12, 14 }
So, P ∩ Q = { 6, 12 }
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Step-by-step explanation:
A={x:xis a natural number}={1,2,3,4,5.....}
B={x:x is an even natural number}={2,4,6,8.....}
C={x:x is an odd natural number}={1,3,5,7,9.......}
D={x:xis a prime number}={2,3,5,7....}
(i) A∩B={x:x is a even natural number}=B
(ii) A∩C={x:x is an odd natural number}=C
(iii) A∩D={x:x is a prime number}=D
(iv) B∩C=ϕ
(v) B∩D={2}
(vi) C∩D={x:xis odd prime number}
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