Math, asked by acutemjulia, 6 months ago

if P = { x | x is natural number between 10 and 16 } and Q = { y | y is an even number between 8 and 20 }, find Q - P.

Answers

Answered by thakkarshilpu1980
25

Step-by-step explanation:

According to the given statements:

P = {11, 12, 13, 14, 15}

Q = {10, 12, 14, 16, 18}

R = {7, 9, 11, 14, 18, 20}

(i) P – Q = {Those elements of set P which are not in set Q}

= {11, 13, 15}

(ii) Q – R = {Those elements of set Q not belonging to set R}

= {10, 12, 16}

(iii) R – P = {Those elements of set R which are not in set P}

= {7, 9, 18, 20}

(iv) Q – P = {Those elements of set Q not belonging to set P}

= {10, 16, 18}

Answered by marishthangaraj
5

Given:

P = { x | x is natural number between 10 and 16 }

P =  { 11 , 12 , 13 , 14 , 15 }

Q = { y | y is an even number between 8 and 20 }

Q = { 10 , 12 , 14 , 16 , 18 }

To find :

Q - P

Solution:

Q - P means the elements of Q which are not the elements of P.

Q - P = { 10 , 12 , 14 , 16 , 18 } - { 11 , 12 , 13 , 14 , 15 }

Q - P = { 10 , 16 , 18 }

Final answer:

Q - P = { 10 , 16 , 18 } .

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