If P ( x ) = x square-2 _/ 2x + 1 , then P (2 _/ 2 ) is equal to
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Answered by
0
Answer:
001.00
Step-by-step explanation:
Answered by
1
Step-by-step explanation:
Solution:
Let p(x) = x^2 - 2√2x + 1,
Therefore, p(2√2) = (2√2)^2 - 2√2(2√2) + 1
= 8 - 8 + 1
= 1
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