Question

If P(x) = x square - 2underroot 2x + 1 then P(2 underroot2) is equal to
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Answer 1

Answer:

1

Step-by-step explanation:

(b) Given, p(x) = x2 – 2√2x + 1 …(i)

On putting x = 2√2 in Eq. (i),

we get,

P(2√2) = (2√2)2– (2√2)(2√2) + 1

= 8 - 8 + 1

= 1

Answer 2

Step-by-step explanation:

Solution:

Let p(x) = x^2 - 2√2x + 1,

Therefore, p(2√2) = (2√2)^2 - 2√2(2√2) + 1

= 8 - 8 + 1

= 1