Question

If P(x)=X square-4x+4 then find the value of p(2)+p(-2)+p(1)

Answer 1

Step-by-step explanation:

P(2)=2^2-4(2)+4

=4-8+4=0

P(-2)=(-2)^2-4(-2)+4

=4+8+4=16

P(1)=1^2-4(1)+4

=2-4+4=1

Therefore,p(2)+p(-2)+p(1)=0+16+1

=17

Answer 2

$\huge\underline\mathfrak\green{Answer:}$

Given, p(x) = x² - 4x + 4

p(2) = (2)² - 4(2) + 4

= 4 - 8 + 4

= 0........................(1)

______________

p(-2) = (-2)² - 4(-2) + 4

= 4 + 8 + 4

= 16.........................(2)

_____________

and

p(1) = (1)² - 4(1) + 4

= 1 - 4 + 4

= 1............................(3)

______________

Adding (1), (2) and (3), we get

p(2) + p(-2) + p(1)

= 0 + 16 + 1

= 17.