Question

If p(x) x squarev- x - 8 then find the zeroes

Answer 1

$x^2-x-8=0\\\\a=1\\\\b=-1\\\\c=-8\\\\D=b^2-4ac\\\\D=(-1)^2-4*1*(-8)\\\\D=1+32\\\\D=33$

x = - b ± √D / 2a

x = (1 ± √33) / 2