Question

if p(x) =x to the power-1 , then find p(1), p(-1)​

Answer 1

Given:

p(x)=x^-1

So,

p(1) = (1)^-1= 1/1=1

p(-1) =(-1)^-1 =1/-1=-1.

Answer 2

Answer:

p(x)=(x)^-1

p(1)= 1^-1

= 1

p(-1)=-1^-1

= -1