Math, asked by anusha025749, 10 months ago

if p(x) =x to the power 2-1 , then find p(1), p(-1)​

Answers

Answered by akshit1229
7

Answer:

p(x) =  {x}^{2}  - 1 \\  \\  \: now \:  \: p(1) =  {1}^{2}  - 1 = 0 \\ p( - 1) =  { - 1}^{2}  - 1 = 0

Answered by lohithchittala
9

p(x) = x² - 1

p(1) = 1² - 1 = 0

p(-1) = (-1)² - 1 = 1-1 =0

Here we should substitute the value in place of x

That's what I did

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