Question

if p(x) =x to the power 2-1 , then find p(1), p(-1)​

Answer 1

Answer:

$p(x) = {x}^{2} - 1 \\ \\ \: now \: \: p(1) = {1}^{2} - 1 = 0 \\ p( - 1) = { - 1}^{2} - 1 = 0$

Answer 2

p(x) = x² - 1

p(1) = 1² - 1 = 0

p(-1) = (-1)² - 1 = 1-1 =0

Here we should substitute the value in place of x

That's what I did

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