Question

If P(x) = x15 – 2018x14 + 2018x13 ………–2018x2 + 2018x and P(2017) = a, then find .a/2017

Answer:

Answer 1

see the image . and to know the answer of the question.

Answer 2

Concept:

Algebraic expressions called polynomials include coefficients and variables. Indeterminates are another name for variables. For polynomial expressions, we can do mathematical operations like addition, subtraction, multiplication, and positive integer exponents, but not division by variable. x2+x-12 is an illustration of a polynomial with a single variable. There are three terms in this illustration: x2, x, and -12.

Given:

P(x) = x¹⁵ – 2018x¹⁴ + 2018x¹³ ………–2018x² + 2018x and P(2017) = a

Find:

a/2017

Solution:

P(x) = x¹⁵ – 2018x¹⁴ + 2018x¹³ ………–2018x² + 2018x

P(2017) = a

P(x) = x¹⁵ – (2017+1)x¹⁴ + (2017+1)x¹³ ………–(2017+1)x² + (2017+1)x

P(2017) = 2017¹⁵ – (2017+1)(2017)¹⁴ + (2017+1)(2017)¹³ ………–(2017+1)(2017)² +                           (2017+1)x

              =2017¹⁵-2017¹⁵+2017¹⁴

                2017¹⁴-2017¹⁴+2017¹³

                .

               .

                .

                 .

               2017²+2017

Alll the terms will get cancelled, only 2017 will left.

P(2017)=2017

So, a/2017=2017/2017

                 =1

Therefore, the solution to a/2017=1

#SPJ3