Math, asked by sherrya, 1 year ago

if p(x)=x² - 2√2x + 1, then find value of p(2√2).

Answers

Answered by RvChaudharY50
55
  • 1

Given :- p(x)=x² - 2√2x + 1

To Find :- The value of p(2√2) ?

Concept used :-

  • The value of a polynomial can be calculated by substituting the variable with given number .

Solution :-

given polynomial is :-

→ p(x) = x² - 2√2x + 1

variable is :-

→ x

So, in order to find p(2√2), substituting x = 2√2 in the given polynomial p(x) we get,

→ p(2√2) = (2√2)² - 2√2•(2√2) + 1

→ p(2√2) = (2)²•(√2)² - (2×2)•(√2×√2) + 1

→ p(2√2) = 4•2 - 4•2 + 1

→ p(2√2) = 8 - 8 + 1

→ p(2√2) = 0 + 1

→ p(2√2) = 1 (Ans.)

Therefore, the value of given polynomial at 2√2 is equal to 1 .

Hence, The value of p(2√2) is equal to 1 .

Learn more :-

solution of x minus Y is equal to 1 and 2 X + Y is equal to 8 by cross multiplication method

https://brainly.in/question/18828734

Answered by sabarigauri449
6

Step-by-step explanation:

Maths my passion ......

Attachments:
Similar questions