Question

 If p(x)=x²-2 then A) p(2)=2&p(-2)=2 B) p(3)=3&p(-2)=0 A) p(0)=0&p(-2)=0 A) p(-3)=0&p(-2)=2​

Answer 1

Answer:

Correct option is

B

1

p(x)=x

2

−2

2

x+1

p(2

2

)=+2

2

2

−2

2

×2

2

+1

p(2

2

)=8−8+1

p(2

2

)=1

Hence, option B.