Question

if p(x)=x²-2 then find p(0),p(2)?​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

-4

Step-by-step explanation:

p (x) = x^2 -2

p (0) - p (2)

p(0)=(0)^2 -2 =0-2= -2

p(2) =(2)^2=4-2=2

p(0)-p(2)= -2-2= -4