Question

If p(x) = x2 – 272x+1, then find the value of p(272)​

Answer 1

$\large \rm p(x) = {x}^{2} - 272x + 1 \\ \\ \large \rm p(272) = {(272)}^{2} - (272 \times 272) + 1 \\ \\ \large \rm p(272) = \cancel{ {(272)}^{2} } - \cancel{ {(272)}^{2}} + 1 \\ \\ \boxed {\blue{\large \bf p(272) =1}}$

Answer 2

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Answer Details :

• Subjects : Math
• Class : Junior High