Question

If p(x)=x²-2x-3

a) Find p(3) ?

b) Check whether x+1 is a factor of p(x) or not?

c) Write p(x) as the product of two first degree polynomials?​

Answer 1

Answer:

a.. given , p(x) =x²-2x-3

let x=3 , then

p(3) = 3²-2(3)-3

= 9-6-3

=9-9

p(x) =0.

Answer 2

Step-by-step explanation:

a.... given , p(x) = x2-2x-3

let x=3 , than

p(3) = 32-2(3) -3

= 9-6-3

= 9-9

= p(x) =0