Question

if p(x)=x2+2x-3,then find p(0),p(√2),p(5)?

Answer 1

Answer:

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Step-by-step explanation:

$p(x) = {x}^{2} + 2x - 3 \\ p(0) = {0}^{2} 2 \times 0 - 3 \\ \: \: \: \: \: \: \: \: = - 3 \\ p( \sqrt{2}) = ({ \sqrt{2} })^{2} + 2 \sqrt{2} - 3 \\ \: \: \: \: \: \: \: \: \: \: \: \: = 2 + 2 \sqrt{2} - 3 \\ \: \: \: \: \: \: \: \: \: \: \: \: = - 5 + 2 \sqrt{2} \\ p(5) = {5}^{2} + 2 \times 5 - 3 \\ \: \: \: \: \: \: \: \: \: \: = 25 - 10 - 3 \\ \: \: \: \: \: \: \: \: \: \: = 25 - 13 = 12 \\ \\ \large\boxed{ \fcolorbox{red}{lime}{hope \: it \: help \: you}}$

Answer 2

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