Question

if p(x)=x2+2x+4, then find p(2), p(0).​

Answer 1

Answer:

$p(x) = {x}^{2} + 2x + 4 \\ \\ p(2) = {2}^{2} + 2 \times 2 + 4 \\ \\ = 4 + 4 + 4 = 12 \\ \\ p(0) = {0}^{2} + 2 \times 0 + 4 \\ \\ = 0 + 0 + 4 = 4$

Answer 2

Answer:

2²+2(2)+4

4+4+4

16

0²+2(0)+4

0+0+4

4