Question

If p(x) = x²+3/4x²-5/16x+1, find p(-2)+(-3)​

Answer 1

Step-by-step explanation:

$p(x) = ( {x})^{2} + { (\frac{3}{4x} )}^{2} - \frac{5}{16x} + 1 \\ p( - 5) = ( { - 5})^{2} + { (\frac{3}{4 \times - 5} )}^{2} - \frac{5}{16 \times- 5} + 1 \\ p( - 5) = 25 + { (\frac{3}{20} )}^{2} + \frac{5}{ -80} + 1 \\ p( - 5) = 25 + { \frac{9}{400} } + \frac{5}{ 80} + 1 \\ p( - 5) = { (\frac{1000 + 9 + 25 + 400}{400} )} \\ p( - 5) = \frac{1434}{400} \\ p( - 5) = \frac{358.5}{100} \\ p( - 5) =3.585$