Math, asked by coolyoradhika97, 4 months ago

If p(x) = x2-3root3 x-1, find p(-1)

Answers

Answered by negivardhan993
1

Explanation:

Given,

\mathsf{p(x)=x^2-3\sqrt3x-1}

Hence, to find p(-1), we have to substitute the value of x in p(x) with -1.

\mathsf{p(-1)=(-1)^2-3\sqrt3(-1)-1}

\mathsf{=1+3\sqrt3-1}

\mathsf{=3\sqrt3}

Answer: 3√3

I hope this helps. :D

Similar questions