Question

If p(x) = x2-3root3 x-1, find p(-1)

Answer 1

Explanation:

Given,

$\mathsf{p(x)=x^2-3\sqrt3x-1}$

Hence, to find p(-1), we have to substitute the value of x in p(x) with -1.

∴ $\mathsf{p(-1)=(-1)^2-3\sqrt3(-1)-1}$

$\mathsf{=1+3\sqrt3-1}$

$\mathsf{=3\sqrt3}$

Answer: 3√3

I hope this helps. :D