Question

If p(x) = X2+3x+1 then find p=(1) p=(2) p(0) p(-1) p (-2)

Answer 1

Answer:

p(2)= 2×2+3×2+1

= 4+6+1

= 11

p(0)=0×2+3×0+1

=0+0+1

=1

p(-1)=(2×-1)+(3×-1)+1

=(-2)+(-3)+1

= -5+1

=-4

p(-2)=(2×-2)+(3×-2)+1

=(-4)+(-6)+1

=-10+1

=-9

Step-by-step explanation:

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Answer 2

Answer:

p(1) = (1)²+3(1)+1

= 1+3+1

= 5.

p(2) = (2)²+3(2)+1

= 4+6+1

= 11

p(0) = (0)²+3(0)+1

= 0+0+1

= 1

p(-1)= (-1)²+3(-1)+1

= 1-3+1

= -2+1

= -1

p(-2)= (-2)²+3(-2)+1

= 4-6+1

= -1

THIS IS YOUR ANSWER