Question

if p(x)=x²-3x+2,find p(0),p(1),p(-1)p(2)​

Answer 1

Step-by-step explanation:

Here

p(0)=x²–3x+2= (0)²-3(0)+2 = 0-0+2 = 2

p(1)=(–1)²–3(–1)+2= 1+3+2 = 6

p(2)= (2)²-3(2)+2 = 4–6+2= 4–4 = 0