Question

if p[x]=x2-3x+2 then find p[1] and p[-2]

Answer 1

p(x)=x2-3x+2

p(-2)=(-2) ×2-3×(-2)+2

p(-2)=-4+6+2

p(-2) =2+2

p(-2)=4

Answer 2

P(x) = x² - 3x + 2

• P(1) = 1² - 3 x 1 + 2

1 - 3 + 2 = 0

• P(-2) = ( - 2 ) ² - 3 x - 2 + 2

4 + 6 + 2 = 12