Question

If p(x)=x² -3x -2 then find the value of p(0),p(1),p(2),p(-1), p(-3)

Answer 1

Step-by-step explanation:

given

p(x)=x² -3x -2

if p(0)=(0)^2-3(0)^-2

=0-0-2{3×0=0}

=-2

p(1)= (1)^2-3(1)-2

=1-3-2

=-4

p(2)=(2)^2-3(2)-2

=4-6-2

=-4

p(-1)=(-1)^2-3(-1)-2

=1+3-2

=2

p(-3)=(-3)^2-3(-3)-2

=9+9-2

=18-2

=16