Question

If P (x) = x² + 3x² +3x+1 then find the value,
of P(1)​

Answer 1

p(2)=2^3+3×2^2-2×2+4

p(2)=8+12-4+4

p(2)=24-4

p(2)=20

p(-2)=-2^3+3×-2^2-2×-2+4

p(-2)=-8+12+4+4

p(-2)=20-8

p(-2)=12

p(0)=0^3+3×0^2-2×0+4

p(0)=0+0+0+4

p(0)=4

                            <=>

Answer 2

Solution:-

It is given:- p(x) =  x² + 3x² +3x+1

And we have to find the value of p(1)

So, p(1) = 1² + 3(1)² + 3(1) + 1    (Substituting the values..)

            = 1 + 3 + 3+ 1

            = 8

Answer:- The value of p(1) = 8