Question

If p(x) = x2 - 4x + 2 then find p(2 -
$\sqrt{2}$
)?​

Answer 1

Answer:

$p(x) = {x}^{2} - 4x + 2 \\ \\ p(2 - \sqrt{2} ) \\ = {(2 - \sqrt{2} )}^{2} - 4(2 - \sqrt{2} ) + 2 \\ = 4 + 2 - 4 \sqrt{2} - 8 + 4 \sqrt{2} + 2 \\ = 0$

So 2 - √2 is a root of polynomial