Question

if p(x)=x2-4x+3 evaluate p(2)+p(-1)+p(0)

Answer 1

Answer:

Given -

p(x) = x²-4x+3

To find -

p(2) + p(-1) + p(0)

Solution -

p(x) = x²-4x+3

p(2)= (2)²-4×2+3

p(2)= 4-8+3

p(2)= 7-8

p(2)= - 1

p(x)= x²-4x+3

p(-1)= (-1)²-4(-1)+3

p(-1)= 1+4+3

p(-1)= 8

p(x)= x²-4x+3

p(0)= (0)²-4×0+3

p(0)= 0-0+3

p(0)= 3

Now,

=p(2) + p(-1)+ p(0)

= - 1+8+3

= - 1+11

= 10

Answer 2

Answer:

10

Step-by-step explanation:

first we find the value of the equation with p=2

(2)^2-4X2+3 = 4-8+3 = 7-8 = -1   --------------- (1)

then we find the value of the equation with p=-1

(-1)^2-4X-1+3 = 1+4+3 = 8      ---------------(2)

then we find the value of the equation with p=0

(0)^2-4X0+3 = 0-0+3 = 3     ------------(3)

then we substitute (1), (2) and (3)

p(2)+p(-1)+p(0)

=> -1+8+3

=> 10

So the answer is 10

Hope you find it helpful :)