Question

if p(x) = x2 - 4x + 3 evaluate p(x) - p (-1) +p(1/2)​

Answer 1

Step-by-step explanation:

$p(x) = {x}^{2} - 4x + 3$

$p(x) - p( - 1) + p( \frac{1}{2} )$

$= {x}^{2} - 4x + 3 - ( {( - 1)}^{2} - 4( - 1) + 3)) + ({ \frac{1}{2} })^{2} - 4 \times \frac{1}{2} + 3$

$= {x}^{2} - 4x + 3 - ((1 + 4 + 3) + \frac{1}{4} - 2 + 3$

${x}^{2} - 4x + 3 - (8 + \frac{1}{4} + 1)$

$= {x}^{2} - 4x + 3 - ( \frac{32 + 1 + 4}{4} )$

$= {x}^{2} - 4x + 3 - ( \frac{37}{4})$

${4x}^{2} - 16x + 12 - 37 = 0$

$4 {x}^{2} - 16x - 25 = 0$