Question

If p(x) =x2-4x+3,find p(2)+p(1/2)-p(-1)​

Answer 1

Answer:

6

Step-by-step explanation:

p(2)= 2(2)-4(2)+3=-1

p(1/2)=1/2(2)-4(1/2)+3=1-2+3=2

p(-1)=-2+4+3=5

p(2)+p(1/2)-p(-1)=-1+2+5=6

Answer 2

Answer:

Step-by-step explanation:

p(x)=$x^{2} -4x +3$

$p(2) = 2^{2} - 4(2) + 3 = 4 - 8 + 3 = -1$

then $p(\frac{1}{2}) = (\frac{1}{2}) ^{2} - 4(\frac{1}{2}) + 3 = \frac{1}{4} - 2 + 3 = \frac{1}{4} + 1 =\frac{5}{4}$

then $p(-1) = (-1)^{2} - 4(-1) + 3 = 1 + 4 + 3 = 8$

so $p(2) + p(\frac{1}{2}) + p(-1) = -1 + \frac{5}{4} - 8 = -9 + \frac{5}{4} = \frac{-36+5}{4} = \frac{-31}{4}$