Question

If p (x)=x²-4x+3, then evaluate p(2)-p(-1)+p(0)

6

- 6

10

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Answer 1

EXPLANATION.

⇒ P(x) = x² - 4x + 3.

As we know that,

⇒ p(2) = (2)² - 4(2) + 3.

⇒ p(2) = 4 - 8 + 3.

⇒ p(2) = 7 - 8.

⇒ p(2) = - 1.

⇒ p(-1) = (-1)² - 4(-1) + 3.

⇒ p(-1) = 1 + 4 + 3.

⇒ p(-1) = 8.

⇒ p(0) = (0)² - 4(0) + 3.

⇒ p(0) = 3.

To find :

⇒ p(2) - p(-1) + p(0).

⇒ (-1) - (8) + (3).

⇒ - 1 - 8 + 3.

⇒ - 9 + 3 = - 6.

⇒ p(2) - p(-1) + p(0) = - 6.

Answer 2

Given :-

p(x) = x² - 4x + 3

To Find :-

p(2) - p(-1) + p(0)

Solution :-

p(x) = x² - 4x + 3

Putting x = 0

p(0) = (0)² - 4(0) + 3

p(0) = 0 - 0 + 3

p(0) = 3

Putting x = -1

p(-1) = (-1)² - 4(-1) + 3

p(-1) = 1 - (-4) + 3

p(-1) = 1 + 4 + 3

p(-1) = 8

Putting x = 2

p(2) = (2)² - 4(2) + 3

p(2) = 4 - 8 + 3

p(2) = -1

Now,

p(2) - p(-1) + p(0)

-1 - (8) + 3

-9 + 3

-6