Question

If P(x)=x²-4x+3 then evaluate P(2)-P(-1)+P(½)

Answer 1

Step-by-step explanation:

P(x)=x²-4x+3

so,

p(2)= 2²-4×2+3= 4-8+3= (-1)

p(-1)= (-1)²-4(-1)+3= 1+4+3= 8

p(1/2)= (1/2)²-4(1/2)+3= (1/4)-2+3 =1/4+1 =5/4

now,

p(2)+p(-1)-p(1/2)

=(-1)+8-5/4

=7-5/4

=28-5/4

= 23 / 4

Answer 2

Step-by-step explanation:

$\bf \underline{Solution-}$

We have p(x) = x² - 4x + 3

p(2) - p(-1) + p(1/2)

= (2² - 4 × 2 + 3) - {(-1)² - 4(-1) + 3} + {(½)² - 4 × ½ + 3}

= (4 - 8 + 3) - (1 + 4 + 3) + (¼ - 2 + 3)

= - 1 - 8 + ⁵/₄

= - 9 + ⁵/₄

= (-36 + 5)/4

= -31/4 Ans.