If p(x) = x2 – 4x + 3, then find p(2) – p(-1).
Answers
Answered by
2
hey mate.
here is your answer
p(x)=x^2-4x+3
p(2)=(2)^2-4(2)+3
p(2)=4-8+3=-1
p(-1)=(-1)^2-4(-1)+3
p(-1)=1+4+3=8
p(2)-p(-1)=-1-8=-9
-9 is your answer
hope it helps
here is your answer
p(x)=x^2-4x+3
p(2)=(2)^2-4(2)+3
p(2)=4-8+3=-1
p(-1)=(-1)^2-4(-1)+3
p(-1)=1+4+3=8
p(2)-p(-1)=-1-8=-9
-9 is your answer
hope it helps
karanchahar200p94w86:
thanks bro more questions are comming
Answered by
1
Heya !!!
P(X) = X²-4X+3
Putting X = 2 in P(X).
P(2) = (2)² - 4 × 2 + 3
=> 4 - 8 + 3
=> 7 -8 = -1
And,
P(-1) = (-1)² - 4 × -1 + 3
=> 1 + 4 + 3 => 8
Therefore,
P(2) - P(-1) => -1 - (8) = -1 - 8 = -9
HOPE IT WILL HELP YOU...... :-)
P(X) = X²-4X+3
Putting X = 2 in P(X).
P(2) = (2)² - 4 × 2 + 3
=> 4 - 8 + 3
=> 7 -8 = -1
And,
P(-1) = (-1)² - 4 × -1 + 3
=> 1 + 4 + 3 => 8
Therefore,
P(2) - P(-1) => -1 - (8) = -1 - 8 = -9
HOPE IT WILL HELP YOU...... :-)
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