if p(x)=x²-4x+4 then find the value of p(2)+p(-2)+p(1)
Answers
Answered by
12
Answer:
17
Step-by-step explanation:
given p(x)=x^2-4x+4
p(2)=(2)^2-4(2)+4=4-8+4=0
p(-2)=(-2)^2-4(-2)+4=4+8+4=16
p(1)=(1)^2-4(1)+4=1-4+4=1
p(2)+p(-2)+p(1)=0+16+1
=17
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srilakshmi23:
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what are you studying ??
are you understood 2nd problem tell me
yes
third
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ok
represent √8.5 on the number line
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Answered by
7
Answer:
p(2)= (2)^2- 4(2)+ 4
4-8+4
=0
p(-2)= (-2)^2- 4(-2)+ 4
4+8+4
16
p(1)= (1)^2- 4(1)+ 4
1-4+4
=1
so,
p(2)+p(-2)+p(1)=
0+16+1
=17
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